Welcome
You are now looking at the Zero Institutes, Theoretical Hadron Collider. We here at the Zero Institute are proud that we are building the least complicated machine ever built, with a total of zero moving parts, it is powered by a Toshiba laptop. It is the largest(and only) theoretically working Canadian particle accelerator. No more will Canadians have to borrow American particle accelerators to theoretically test our theoretical physics.We now have a particle accelerator here In Canada, theoretically.
On Feb 16th 2015, the Zero Institute is happy to announce that the THC produced it's first theoretical particle beam, the graphs can be found below.
We ask that individuals refrain from smoking during THC operations as there is the possibility some very volatile chemical vapors being theoretically produced.
Enjoy your visit to the THC, the smallest particle accelerator on earth, so small it theoretically does not exists.
***THC Engineers Are Currently Showing Signs Of Radiation Sickness***
...Though Medical Our Staff Believes That The Rash Is Due To A Nickle Allergy
... And That Radiation Exposure From A Particle Accelerator That Only Exists On Spreadsheets Is Theoretically Impossible,
If, at your visit to the THC You Exhibit Any Of The Following Symptoms:
Rash
Tooth Loss
Hair Loss
Vomiting
Flaking Skin
Disorientation
!!!Seek Medical Attention Immediately!!!
***The THC Has Accidentally Opened An Inter Dimensional Rift***
***Due To The Inter Dimensional Rift***
Seek Security Staff Immediately If You Experience:
Time Distortion
Quantum Displacement
The Growth Of Horns, Tail Or Wings
The Ability To Shoot Plasma From Hands
The Uncontrollable Urge To Consume Human Flesh
The Ability To Either Breath Fire, Or Shoot Fire Or Lightning From Ones Eyes
***The THC Is Under Repair And Expansion***
THC Operations Will likely Resume on Feb 23 2015
Thank You For Your Patience, Here is a very long and boring calculation.
To Help Zeno Reach The Wall
ok 1/4 to the wall, in 1-100 measure scale. ->25 towards wall, also +>25 away from the point of origin. 25-25=0 New point of origin=0=25and0. Next move ->6.25(2)=12.5 towards wall, also +>6.25(2)=12.5 away from point of origin[(2) because there are two points of origin]. Next move, position fifty ->
The point is, each new position measured is zero, because of the position moved towads the wall is relative to the move away from the point of origin.
Is the second position (2) or + twenty five? I am not sure as of yet... A lot of thinking lies ahead now, there is a BIG answer here somewhere.
Your position is always zero, and how far you have to go, is relative to how far you have come. How relative, is the question.
25+(6.25*2)+1.5625*[2(3)]+0.390625*[2*3(4)]!!!+[[[0.09765625*[[(2*3)4]5]+0.09765625
!!!across half way to wall, it goes exponential!!!
0.09765625
17.578125
0.0244140625
0.006103515625
pos 5, 11.71875+56.25=67.96875
pos 6, =85.546875
pos 7, =116.30859375
<- End
Wait, I overshot the wall, one always must overshoot the wall though, lest one not know one touches it.
1/16th to the wall 1-100 scale
pos 1, 6.25
0.390625
0.048828125
pos 2, 6.298828125
0.0244140625
0.00152587890625
pos 3, 6.30035400390625
0.00152587890625
0.0091552734375
pos 4, 6.30950927734375
0.000095367431640625
0.002288818359375
pos 5, 6.311798095703125
0.0000059604644775390625
0.0007152557373046875
pos 6, 6.3125133514404296875
0.00000037252902984619140625
0.0002682209014892578125
pos 7, 6.3127815723419189453125
0.000000023283064365386962890625
0.00011734664440155029296875
pos 8, 6.31289891898632049560546875
1.4551915228366851806640625e-9
0.000058673322200775146484375
pos 9, 6.312957592308521270751953125
9.094947017729282379150390625e-11
0.0000330037437379360198974609375
pos 10, 6.312957592308521270751953125
5.684341886080801486968994140625e-12
2.06273398362100124359130859375e-5
pos 11, 6.3129782196483574807643890380859
3.5527136788005009293556213378906e-13
8.8633100858714897185564041137695e-7
pos 12,
2.2204460492503130808472633361816e-14
1.0635972103045787662267684936523e-5
pos 13
1.3877787807814456755295395851135e-15
8.6417273337247024755924940109251e-6
pos 14
8.6736173798840354720596224069594e-17
7.5615114170091146661434322595595e-6
pos 15 (I think the transition from deceleration to acceleration happens in between 15 and 16 because 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 is just as acceptable as 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16 and the zero seems to occupy more than a mere place holder)
5.4210108624275221700372640043496e-18
7.088916953446044999509467743337e-6
pos 16(and my number clearly stops decelerating, and starts to accelerate towards the wall)
3.3881317890172013562732900027185e-19
7.088916953446044999509467743337e-6
pos 17
2.1175823681357508476708062516991e-20
7.5319742630364228119788094772956e-6
pos 18
1.3234889800848442797942539073119e-21
8.4734710459159756634761606619577e-6
pos 19
8.2718061255302767487140869206994e-23
1.0062246867025221100377940786074e-5
pos 20
5.1698788284564229679463043254371e-24
1.2577808583781526375472425982593e-5
pos 21
3.2311742677852643549664402033982e-25
1.6508373766213253367807559102153e-5
pos 22
2.0194839173657902218540251271239e-26
2.2699013928543223380735393765461e-5
pos 23
1.2621774483536188886587657044524e-27
3.2629832522280883609807128537851e-5
pos 24
7.8886090522101180541172856528275e-29
4.8944748783421325414710692806774e-5
pos 25
4.9303806576313237838233035330172e-30
7.6476169974095820960485457510585e-5
pos 26
3.0814879110195773648895647081358e-31
1.242737762079057090607888684547e-4
pos 27
1.9259299443872358530559779425849e-32
2.0971199735084088404008121551731e-4
pos 28
1.2037062152420224081599862141156e-33
3.669959953639715470701421271553e-4
pos 29
7.5231638452626400509999138382225e-35
6.65180241597198429064632605469e-4
pos 30
4.7019774032891500318749461488891e-36
0.00124721295299474705449618613525
pos 31
2.9387358770557187699218413430557e-37
0.00241647509642732241808636063706
pos 32
1.8367099231598242312011508394098e-38
0.00483295019285464483617272127411
pos 33
1.1479437019748901445007192746311e-39
0.00996795977276270497460623762785
pos 34
7.1746481373430634031294954664444e-41
0.02118191451712074807103825495919
pos 35
4.4841550858394146269559346665278e-42
0.04633543800620163640539618272322
pos 36
2.8025969286496341418474591665799e-43
0.10425473551395368191214141112726
pos 37
1.7516230804060213386546619791124e-44
0.24108907587601788942182701323178
pos 38
1.0947644252537633366591637369453e-45
0.57258655520554248737683915642547
pos 39
6.8422776578360208541197733559081e-47
1.3956797283135098129810454437871
pos 40
4.2764235361475130338248583474426e-48
3.4891993207837745324526136094679
pos 41
2.6727647100921956461405364671516e-49
8.9410732595084222394098223742614
pos 42
1.6704779438076222788378352919698e-50
23.470317306209608378450783732436
pos 43
1.0440487148797639242736470574811e-51
63.076477760438322517086481280923
pos 44(the wall oblitomiser)
6.5253044679985245267102941092569e-53
173.46031384120538692198782352253
1/16, of 1/16, of 1/16 will destroy the wall and anything behind it. No, there are computer programs to start dealing with 1/512 and so forth. I am surmising that 1/infinity(I need to learn the infinity packaging and bundling math language) will place one at zero, or any point one wishes.
